Skip to content

Instantly share code, notes, and snippets.

@IanMcT
Created November 8, 2016 17:45
Show Gist options
  • Star 0 You must be signed in to star a gist
  • Fork 0 You must be signed in to fork a gist
  • Save IanMcT/394542f4537094b349b5423a163dcf61 to your computer and use it in GitHub Desktop.
Save IanMcT/394542f4537094b349b5423a163dcf61 to your computer and use it in GitHub Desktop.
#Sudoku solver
#by http://stackoverflow.com/questions/1697334/algorithm-for-solving-sudoku
#username hari
#Solves Sudoku puzzles.
def findNextCellToFill(grid, i, j):
for x in range(i,9):
for y in range(j,9):
if grid[x][y] == 0:
return x,y
for x in range(0,9):
for y in range(0,9):
if grid[x][y] == 0:
return x,y
return -1,-1
def isValid(grid, i, j, e):
rowOk = all([e != grid[i][x] for x in range(9)])
if rowOk:
columnOk = all([e != grid[x][j] for x in range(9)])
if columnOk:
# finding the top left x,y co-ordinates of the section containing the i,j cell
secTopX, secTopY = 3 *(i//3), 3 *(j//3)
for x in range(secTopX, secTopX+3):
for y in range(secTopY, secTopY+3):
if grid[x][y] == e:
return False
return True
return False
def solveSudoku(grid, i=0, j=0):
i,j = findNextCellToFill(grid, i, j)
if i == -1:
return True
for e in range(1, 10):
if isValid(grid, i, j, e):
grid[i][j] = e
if solveSudoku(grid, i, j):
return True
# Undo the current cell for backtracking
grid[i][j] = 0
return False
input = [[0, 0, 6, 0, 2, 0, 8, 0, 0],
[0, 1, 0, 0, 0, 0, 0, 7, 0],
[2, 0, 0, 7, 0, 3, 0, 0, 5],
[8, 0, 0, 1, 3, 6, 0, 0, 4],
[0, 0, 0, 0, 0, 0, 0, 0, 0],
[1, 0, 0, 2, 5, 8, 0, 0, 6],
[9, 0, 0, 8, 0, 7, 0, 0, 2],
[0, 7, 0, 0, 0, 0, 0, 5, 0],
[0, 0, 2, 0, 4, 0, 6, 0, 0]]
solveSudoku(input)
print(input)
Sign up for free to join this conversation on GitHub. Already have an account? Sign in to comment