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Created June 24, 2020 04:35
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s8.py
l1=[(1,2,3),(3,1,1),(8,5,3),(3,4,2)]
#Sorted based on second element in the tuple.lambda function returns second element in the tuple
print (sorted(l1,key=lambda x:x[1]))
#Output:[(3, 1, 1), (1, 2, 3), (3, 4, 2), (8, 5, 3)]
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