Created
September 6, 2019 02:26
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# @param {String} s | |
# @return {Integer} | |
def length_of_longest_substring(s) | |
chars = s.split('') | |
longest = 0 | |
base = 0 | |
char_set = Set.new | |
(base...chars.length).each do |iter| | |
while char_set.include?(chars[iter]) | |
# move base up and until the dup char is found | |
# this acts as a sliding window | |
char_set.delete(chars[base]) | |
base += 1 | |
end | |
# increment longest only when no dup | |
len = iter - base + 1 | |
longest = len if len > longest | |
char_set.add(chars[iter]) | |
end | |
longest | |
end | |
# expected 3 | |
puts length_of_longest_substring('abcabcbb').inspect | |
# expected 3 | |
puts length_of_longest_substring('pwwkew').inspect | |
# same chars, epxected 1 | |
puts length_of_longest_substring('bbb').inspect | |
# longest in the end, expected 9 | |
puts length_of_longest_substring('pdxdsprlong').inspect | |
# longest in the front, expected 9 | |
puts length_of_longest_substring('sprlongdxd').inspect |
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