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@JacobMJones
Created November 15, 2023 22:40
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A star path finding explanation in python
# The total cost of a node is calculated as
# f(n) = g(n) + h(n)
# g(n) is the cost from the start node to the current node, and
# h(n) is the estimated cost from the current node to the goal.
# f value is the sum of g and h and is used to compare nodes when deciding
# the parent attribute of a Node
# is used to keep track of the path
# from the start node to the current node.
class Node:
def __init__(self, position=None, parent=None):
self.position = position
self.parent = parent
self.g = 0
self.h = 0
self.f = 0
# Compare nodes
def __eq__(self, other):
return self.position == other.position
######################################################
# astar is the main function
# start is where the node begins and end_node is the goal
#open list is for nodes that have been discovered but not evaluated. It begins
#with the start node, new nodes (neighbors of the currently evaluated nodes) are added to this list.
#these are potential candidates for path continuation
#the algorithm will judge based on their f values.
#closed list is for nodes whose neighbours f values have been evaluated
#The algorithm terminates when the goal node is added to the closed list
def astar(grid, start, end):
# Create start and end node
start_node = Node(start, None)
end_node = Node(end, None)
print(f"Start: {start_node.position}")
print(f"End: {end_node.position}")
# Initialize open and closed list
open_list = []
closed_list = []
# Add the start node
open_list.append(start_node)
# Loop until the end node is found
while len(open_list) > 0:
# print('open', [node.position for node in open_list])
# Get the current node (node with the lowest f value)
current_node = open_list[0]
current_index = 0
for index, item in enumerate(open_list):
if item.f < current_node.f:
current_node = item
current_index = index
# Pop current node from open list and add to closed list
open_list.pop(current_index)
closed_list.append(current_node)
# Check if we reached the end
if current_node == end_node:
path = []
current = current_node
while current is not None:
path.append(current.position)
current = current.parent
return path[::-1] # Return reversed path
# Generate children
children = []
for new_position in [(0, -1), (0, 1), (-1, 0), (1, 0)]: # Adjacent squares
node_position = (current_node.position[0] + new_position[0], current_node.position[1] + new_position[1])
# Make sure within range
if node_position[0] > (len(grid) - 1) or node_position[0] < 0 or node_position[1] > (len(grid[len(grid)-1]) -1) or node_position[1] < 0:
continue
# Make sure walkable
if grid[node_position[0]][node_position[1]] != 0:
continue
# Create new node and set current node as parent
new_node = Node(node_position, current_node)
# Append
children.append(new_node)
# Loop through children
for child in children:
# Child is on the closed list
if len([closed_child for closed_child in closed_list if closed_child == child]) > 0:
continue
# Create the f, g, and h values
child.g = current_node.g + 1
child.h = ((child.position[0] - end_node.position[0]) ** 2) + ((child.position[1] - end_node.position[1]) ** 2)
child.f = child.g + child.h
# Child is already in the open list
if len([open_node for open_node in open_list if child == open_node and child.g > open_node.g]) > 0:
continue
# Add the child to the open list
open_list.append(child)
return None # No path found
# Example usage
grid = [[0, 0, 0, 0, 0],
[0, 1, 1, 1, 0],
[0, 1, 0, 0, 0],
[0, 0, 0, 1, 1],
[0, 0, 0, 0, 0]]
start = (0, 0)
end = (4, 4)
path = astar(grid, start, end)
#print(path)
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