Apply similar behaviour to Array.join to an Object

Object.join.js

Object.prototype.join = function (separator, template)
{
	var key
	    , output = []
	    , length = 0 
	    , self = this
	    , tKey = '{key}'
	    , tValue = '{value}';

	separator = separator || ',';
	template = template || [tKey, tValue].join(':');

	for (key in self)
	{
		if (self.hasOwnProperty(key))
		{
			output[length++] = template.split(tKey).join(key).split(tValue).join(this[key]);
		}
	}
	
	return output.join(separator);
};

Three quick examples below...

var oExample = {
    age: 28
    , forename: 'Jamie'
    , github: 'https://github.com/JamieMason'
    , surname: 'Mason'
},
oLogging = {
    'No Arguments': oExample.join()
    , 'With seperator': oExample.join(' | ')
    , 'With seperator and template': oExample.join(',\n', '<strong>{key}</strong> {value}')
    , 'With seperator and template (2)': oExample.join('\n', '{key} ({value})')
};

console.log(oLogging.join('\n\n', '{key}\n-----\n{value}'));

Above example outputs...

No Arguments
-----
age:28,forename:Jamie,github:https://github.com/JamieMason,surname:Mason

With seperator
-----
age:28 | forename:Jamie | github:https://github.com/JamieMason | surname:Mason

With seperator and template
-----
<strong>age</strong> 28,
<strong>forename</strong> Jamie,
<strong>github</strong> https://github.com/JamieMason,
<strong>surname</strong> Mason

With seperator and template (2)
-----
age (28)
forename (Jamie)
github (https://github.com/JamieMason)
surname (Mason)