Error: Setting StartMenu layout using C# - dynamically

StartMenuLayout.cs

/*!
 * GPII Windows 10 Start Menu Layout Setter.
 *
 * Copyright 2018 Raising the Floor - International
 *
 * Licensed under the New BSD license. You may not use this file except in
 * compliance with this License.
 *
 * The research leading to these results has received funding from the European Union's
 * Seventh Framework Programme (FP7/2007-2013)
 * under grant agreement no. 289016.
 *
 * You may obtain a copy of the License at
 * https://github.com/GPII/universal/blob/master/LICENSE.txt
 */

using System;
using System.IO;
using System.Linq;
using System.Text;
using System.Collections;
using System.Collections.ObjectModel;
using System.Threading;
using System.Threading.Tasks;
using System.Management.Automation;
using System.Management.Automation.Runspaces;

public class Startup {
        static void Main(string[] args) {
        Type t = Type.GetType("Microsoft.Windows.StartLayout.Commands.CLSID_StartLayoutCmdlet, Microsoft.Windows.StartLayout.Commands, Version=10.0.0.0, Culture=neutral, PublicKeyToken=31bf3856ad364e35, processorArchitecture=MSIL");
        dynamic o = Activator.CreateInstance(t);
        MethodInfo processRecord = t.GetMethod("CLSID_StartLayoutCmdlet", BindingFlags.NonPublic | BindingFlags.Instance);
        o.Path = @"c:\tmp\aa.xml";
        processRecord.Invoke(o, null);
    }
}