regex_AoC_day18.py

import re

#We will be looking to evaluate strings like:
eq1 = "1 + (2 * 3) + (4 * (5 + 6))"
eq2 = "5 + (8 * 3 + 9 + 3 * 4 * 3)"
#Parentheses take preference, then strictly left-to-right

#Let's find the innermost set of parens to evaluate
def findInnerParens(equation):
    pattern = re.compile(r'')
    return re.search(pattern, equation)

print(findInnerParens(eq1))
print(findInnerParens(eq2))

#Given an equation with no parentheses, find the first two numbers
#So we can do an operation on them
def findFirstTwo(equation):
    pattern = re.compile(r'')
    return re.search(pattern, equation)

eq3 = '4 + 63 * 7 + 8'
eq4 = '51 * 7 - 14'

print(findFirstTwo(eq3))
print(findFirstTwo(eq4))