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@JeffreyWay
Created June 7, 2012 14:56
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Simple PHP Quiz
// Fun little quiz
Assuming this string: "January 5th, 2012"
In the shortest amount of code possible, place:
- 'January' within a $month variable
- '5th' within a $day variable
- '2012' within a $year variable.
See if you can accomplish this with one line of code. (And no snarky $month = 'January' answers.
Assume that the format always stays the same, but month, day, and year values can change with each referesh.
@m4tthumphrey
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@thecrypticace Haha good spot! I still think the preg_split method looks alot nicer than sscanf() even though it's a bit longer (6 chars) !

@abennouna
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@JeffreyWay Thanks, didn't know about it. What about non-space separators? Try e.g.

sscanf('2012-25-12', '%d-%d-%d', $y, $m, $d)

It doesn't work. Instead, I'd need:

sscanf('2012-25-12', '%[^-]-%[^-]-%[^-]', $year, $month, $day)

when

list($year, $month, $day) = explode('-' , '2012-25-12');

is ok. Or am I missing something in the sscanf syntax?

@topdown
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topdown commented Jun 7, 2012

// array
date_parse(trim("January 5th, 2012",','));
//vars
extract(date_parse(trim("January 5th, 2012",',')));

@abennouna
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Of course, my calendar has 30 months of 12 days each :D

@xeoncross
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@topdown, what is the point of the trim() since there are no leading/following commas?

Combining @letsallplaygolf with @thecrypticace I get:

extract(date_parse(date('F jS Y')));

@topdown
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topdown commented Jun 7, 2012

@xeoncross trim is stripping the comma
trim has an optional parameter for specifying a character list http://php.net/manual/en/function.trim.php
Wasn't thinking about date_parse already handling it.

@stetodd
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stetodd commented Jun 7, 2012

@topdown I think @xeoncross was pointing out that trim() only trims characters from the beginning/end of a string, not the middle. So trim isn't required in your code :)

@JeffreyWay Nice teaser though. I didn't know about the sscanf() function.

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