Map member functions in python

gistfile1.py

import operator as op

class A:
    def test(self):
        return "self.test()"
    def test2(self,arg):
        return "self.test2({arg})".format(arg=arg)

alist = map(lambda i: A(), range(10))
ans   = map(op.methodcaller('test'), alist)

#can also be used to (rarely) simply things
op.methodcaller('test')(A())

#also works with arguments
op.methodcaller('test2','argument')(A())