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# JimDennis/eratosthenes_sieve.py

Created Jan 5, 2018
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 #!/usr/bin/env python2 ''' Eratosthenes sieve ''' from __future__ import print_function import array import time start = time.time() limit = 2*10**6 # Four million sieve = array.array('l',range(limit)) primes = [2] # Start with just first, then append to it n = 0 # Index into current prime being eliminated while n*n < limit: p = primes[n] # Eliminate all multiples of primes[n]: for i in range(p+p,limit, p): sieve[i] = 0 # Find remaining numbers up to new upperbound (current prime squared) for i in range(primes[-1]+1,min(limit, p*p)): # min() to avoid out of bounds access. if sieve[i]: primes.append(sieve[i]) n+=1 elapsed = start - time.time() print(', '.join(['%s' % x for x in primes[:20]]), "...", ', '.join(['%s' % x for x in primes[-10:]])) print("%d primes found in %g seconds" % (len(primes), elapsed))

### JimDennis commented Jan 5, 2018

For this particular case the use of array.array over just using a plain list seems to give less than a 2% performance benefit.

A quick and dirty test with the limit set at 20 million gives me 10 seconds for the array.array version and 13 seconds for the list version. So that's about a 25% advantage at that scale.