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October 20, 2019 12:46
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BreadthFirst Search Solution
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#include <iostream> | |
#include <algorithm> | |
#include <vector> | |
#include <queue> | |
using namespace std; | |
int n; | |
int main() { | |
cin >> n; | |
vector<int> graph[1005]; | |
int arr[1005]; | |
bool solVisited[1005]; | |
int cityHere[1005]; | |
int prod[1005]; | |
queue<int> q; | |
int capital = 1; | |
for(int i = 0;i<n; ++i) scanf("%d",&arr[i]); | |
for(int i = 0;i<n; ++i) { | |
if(arr[i] != i){ | |
graph[i].push_back(arr[i]); | |
graph[arr[i]].push_back(i); | |
} else { | |
capital = i; | |
} | |
} | |
// set capital when arr[i] == i | |
solVisited[capital] = true; | |
cityHere[capital] = 0; | |
int idx = 0; | |
q.push(capital); | |
while(!q.empty()) { | |
int currentDepth = q.front(); q.pop(); | |
for(auto adjCity : graph[currentDepth]) { | |
if(solVisited[adjCity]) continue; // if we have visited this city ,skip! | |
solVisited[adjCity] = true; // mark present adjacent city to current city as visited | |
//increasing the number at (parent vertex + 1) by 1 | |
cityHere[adjCity] = cityHere[currentDepth] + 1; | |
prod[cityHere[currentDepth]+1]++; | |
// push edge to q | |
q.push(adjCity); | |
} | |
idx++; | |
} | |
for(int i = 1;i<n; ++i) { | |
printf("%d, ", prod[i]); | |
} | |
return 0; | |
} |
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