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December 25, 2015 06:49
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If the number fits in an 8 bit byte, then prepend 0s to make full 8 bit bytes, numbers above 255 get new digits added (like normal binary)
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function DecToBase(IN,BASE) | |
local B,K,OUT,D=BASE or 10,"0123456789ABCDEFGHIJKLMNOPQRSTUVW","" | |
while IN>0 do | |
IN,D=math.floor(IN/B),math.mod(IN,B)+1 | |
OUT=string.sub(K,D,D)..OUT | |
end | |
if string.len(OUT) == 1 then | |
OUT = "0000000" .. OUT | |
elseif string.len(OUT) == 2 then | |
OUT = "000000" .. OUT | |
elseif string.len(OUT) == 3 then | |
OUT = "00000" .. OUT | |
elseif string.len(OUT) == 4 then | |
OUT = "0000" .. OUT | |
elseif string.len(OUT) == 5 then | |
OUT = "000" .. OUT | |
elseif string.len(OUT) == 6 then | |
OUT = "00" .. OUT | |
elseif string.len(OUT) == 7 then | |
OUT = "0" .. OUT | |
elseif string.len(OUT) == 8 then | |
OUT = OUT | |
else | |
OUT = OUT | |
end | |
return OUT | |
end | |
print 'What is your number?' | |
number = io.read() | |
number = tonumber(number) | |
print (DecToBase(number,2)) |
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