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/*4.1 Implement a function to check if a binary tree is balanced. For the purposes of this question, | |
* a balanced tree is defined to be a tree such that the heights of the two subtrees of any node never differ by more than one. | |
*/ | |
// Solution 1 | |
public class Solution { | |
public boolean balancedBinaryTree(TreeNode root) { | |
if(root==null) return true; | |
if(Math.abs(getHeight(root.left)-getHeight(root.right))>1) return false; | |
return balancedBinaryTree(root.left) && balancedBinaryTree(root.right); | |
} | |
public int getHeight(TreeNode root) { | |
if(root==null) return 0; | |
return Math.max(getHeight(root.left), getHeight(root.right))+1; | |
} | |
} | |
// Solution 2 | |
public class Solution { | |
public boolean isBalanced(TreeNode root) { | |
if(checkHeight(root)==-1) { | |
return false; | |
} else { | |
return true; | |
} | |
} | |
public checkHeight(TreeNode root) { | |
if(root==null) return 0; | |
int leftHeight = checkHeight(root.left); | |
if(leftHeight==-1) return -1 | |
int rightHeight = checkHeight(root.right); | |
if(rightHeight==-1 || Math.abs(leftHeight-rightHeight)>1) return -1; | |
return Math.max(leftHeight, rightHeight)+1; | |
} | |
} |
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