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Just-Simple-59/Even and Odd.py

Last active June 22, 2021 18:10
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Ask the user for a number. Depending on whether the number is even or odd, print out an appropriate message to the user.
Raw
Even and Odd.py
Number = int(input("Enter a Random Number\n"))
check = Number % 2
if check == 0:
print("The number you choose" + ' ' + str(Number) + ' ' + "is even")
else:
print("The number you choose" + ' ' + str(Number) + ' ' + "is odd")
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