subSeq.py

# Depending on what you want here are a few solutions!

# One line is always nice and this might also be one of the fastest:
any([input[i-2] == 1 and input[i-1] == 3 and v == 4 for i, v in enumerate(input) if i > 2])

# Some like it dynamic:
getSubSequenceLambda = lambda input: any([input[i-2] == 1 and input[i-1] == 3 and v == 4 for i, v in enumerate(input) if i > 2])

# It's a classic:
func getSubSequenceFunc(input):
    for i, v in enumerate(input):
        # Watchdogs, you love them, or hate them.
        if i < 2:
            continue
        if input[i-2] == 1 and input[i-1] == 3 and v == 4:
            return True
    return False

# So many assumptions. How about strings?
'.1.3.4.' in '.'.join([''] + input + [''])

I didn't have a python console to check available, but it should run ;)