Write a program to prompt the user for hours and rate per hour using raw_input to compute gross pay. Award time-and-a-half for the hourly rate for all hours worked above 40 hours. Put the logic to do the computation of time-and-a-half in a function called computepay() and use the function to do the computation. The function should return a valu…

4.6.py

def computepay(hours,rate):
 if hours>40.0:
  p = rate * 40.0
  p = p+(1.5*rate*(hours-40))
 else:
  p = rate*hours
 return p
hours = float(raw_input("Enter worked hours: "))
rate = float(raw_input("Enter Pay rate per hour: "))
print computepay(hours,rate)

Hello all! I should have updated you all on my progress. My apologies. I actually completed this assignment. Your help is greatly appreciated. :)

Hello everyone!
Can someone plz help me with this problem? I am repeatedly getting the error with this code

Hi guys!!! here's my answear!! I hope it helps you...

def computepay(x,y):
if x>40:
sub = (x - 40) * 1.5
x = 40 + sub
pay = x * y
return pay
ux = input("Enter hour:")
uy = input("Enter rate:")
try:
x = float(ux)
y = float(uy)
except:
print("error,please enter numeric input")
quit()
h=computepay(x,y)
print("Pay",h)

Its not working....its shows error in 2nd line...plz help me ....that how I can solve it..

I am getting an error message "Invalid Syntax"

h=input("enter hours:")
x=float(h)
r=input("enter rate:")
y=float(r)
def computepay(x,y):
if x>40:
p=40y
p=p+(1.5y*(x-40))
else:
p=x*y
return p
print("Pay",computepay(x,y))

def computepay(h,r):
if(h>40):
return (40r)+((r1.5)(h-40))
else:
return hr
hrs = input("Enter Hours:")
rate=input("Enter Rate:")
print("Pay",computepay(float(hrs),float(rate)))

def computepay(h,r):
if h > 40:
p = 1.5 * r * (h - 40) + (40 *r)
else:
p = h * r
return p

hrs = input("Enter Hours:")
hr = float(hrs)
rphrs = input("Enter rate per hour:")
rphr = float(rphrs)

p = computepay(hr,rphr)
print("Pay",p)

working 100%
def salary (hours,rate):
if hours<=40:
p=hoursrate
return p
else:
p=(40rate)+((hours-40)1.5rate)
return p

hours=float(input('Enter Hours:'))
rate=float(input('Enter Rate:'))

pay = salary(hours,rate)

print(pay)

type mismatch ???????

Can you used your own editor to check the results before submitting the code.
As for me I worked fine.

You can also paste your code here so that you can get help

I'm stuck in assignments 4.6,, plz help me

@sourav091998
are you still needing help?

Im getting error in line 2 I have tried ur code

Can you post the error message here

And the question as well. Remember that some time questions are different from person to person

def computepay(h,r):
if h < 40:
Pay = h * r
else:
Pay = 40 * r + (h-40) * 1.5 * r
return Pay

hrs = input("Enter Hours:")
h = float(hrs)
rate = input("Enter Rate:")
r = float(rate)

Pay = computepay(h,r)
print("Pay", Pay)

It works!!!!!!!!!! please use this code~

@persphone997 why didn't you use the try except block?

@persphone997 why didn't you use the try except block?

Cause the original code he gave us is:
def computepay(h,r):
return 42.37

hrs = input("Enter Hours:")
p = computepay(10,20)
print("Pay",p)

So it definitely wants to improve on that.

But in the description did they ask you to use try except or not?

But in the description did they ask you to use try except or not?

For me.
Nope.

Okay then I hope they accepted your code right?

yes～ Abdoulaye Balde <notifications@github.com>于2020年7月10日 周五上午3:51写道：

…

***@***.**** commented on this gist. ------------------------------ Okay then I hope they accepted your code right? — You are receiving this because you commented. Reply to this email directly, view it on GitHub <https://gist.github.com/0696fe56a97c0699c3c5#gistcomment-3370928>, or unsubscribe <https://github.com/notifications/unsubscribe-auth/AQHT5XO4JKKT2NE77E6S3LDR23XDHANCNFSM4H6T7BFA> .

Well done

def computepay(hours,rate):
if hours>40.0:
p = rate * 40.0
p = p+(1.5rate(hours-40))
else:
p = rate*hours
return p
hours = float(raw_input("Enter worked hours: "))
rate = float(raw_input("Enter Pay rate per hour: "))
p=(computepay(hours,rate))
print("Pay",p)

This code is definitely gonna run on any platform.
Just try it once.

def computepay(h,r):
if h>40.0:
p=1.5 * float(r) * (h-40.0)+(40.0 * float(r))
else:
p=h*r
return p
hrs = input("enter hours:")
a=float (hrs)
rate = input("enter rate per hour:")
b=float(rate)
p=computepay(a,rate)
print("Pay",p)

help me my code is not running

solution without def

hrs = input("Enter Hours:")
h = float(hrs)
rate = input("Enter Pay Rate:")
r = float(rate)
pay = hr
otpay = 40r + (h-40)r1.5
if h<=40:
print(pay)
else:
print(otpay)

def computepay(h,r):
if h > 40:
p = 1.5 * r * (h - 40) + (40 *r)
else:
p = h * r
return p

hrs = input("Enter Hours:")
hr = float(hrs)
rphrs = input("Enter rate per hour:")
rphr = float(rphrs)

p = computepay(hr,rphr)
print("Pay", p)

#100% working

Thanks!!!!!!! a tonnnnn it really worked

def computepay(h,r):
if h>40.0:
p = r * 40.0
p = p+(1.5r(h-40))
else:
p = r*h
return p

h = float(input("Enter Hours:"))
r = float(input("Enter rate:"))
p = computepay(h,r)
print("Pay",p)