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Write a program to prompt for a score between 0.0 and 1.0. If the score is out of range, print an error. If the score is between 0.0 and 1.0, print a grade using the following table: Score Grade >= 0.9 print A, Grade >= 0.8 print B, Grade >= 0.7 print C, Grade>= 0.6 print D, Grade < 0.6 print F If the user enters a value out of range, print a su…
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score = float(raw_input("Enter score between 0.0 and 1.0: ")) | |
if score>1.0 or score<0.0 : | |
print "error" | |
elif score>=0.9 : | |
print 'A' | |
elif score>=0.8 : | |
print 'B' | |
elif score>=0.7 : | |
print 'C' | |
elif score>=0.6 : | |
print 'D' | |
else : | |
print 'F' |
score = input('Enter score: ')
s = float(score)
if s >= 0.9 and s <= 1.0:
print('A')
elif s >= 0.8 and s < 0.9 :
print('B')
elif s >= 0.7 and s < 0.8 :
print('C')
elif s >= 0.6 and s < 0.7 :
print('D')
elif s < 0.6 and s > 0.0 :
print('F')
else :
try:
if s <= 0.0 or s >= 1.0 :
print('Error,Score is out of range.Please enter score between 0.0 and 1.0')
except :
quit()
Improve your grogram in Question 1 by adding try and except. If a non-numeric input is
submitted, your program should print a message and exit the program.
Example input and output:
Enter Hours: 50
Enter Rate: ten
Error, please enter a numeric dat
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There was an error but this fixes it:
score=input("Please type a score between 0.0 and 1.0: ")
try:
score = float(score)
except:
print("Bad score")
exit(0)
if float(score) >= 0.9 and float(score) <= 1.0:
print("A")
elif float(score) >= 0.8 and float(score) <= 0.9:
print("B")
elif float(score) >= 0.7 and float(score) <= 0.8:
print("C")
elif float(score) >= 0.6 and float(score) <= 0.7:
print("D")
elif float(score) > 0 and float(score) <= 0.6:
print("F")
else:
print("Bad score")