A Python program that replace all the vowels in the string e.g: “National Center for Supercomputing Applications” by their corresponding order number in alphabetical sequence (a with 1, e with 5, etc). Print the resulting string and the total number of consonants in the given string.

replace_vowels.py

import argparse
    

if __name__ == '__main__':
    parser = argparse.ArgumentParser(
        description="A Python code to replace vowel by numbers corresponding to alphabetical order ")
    
    parser.add_argument("-string", "--string_txt", default="National Center for Supercomputing Applications")
   
    args = parser.parse_args()

    string_txt = args.string_txt
    
    # there maybe libraries that provide these but 
    # I just decided to explicitly manage it myself
    vowel = {'a', 'e', 'i', 'o', 'u', 'y'}
    alphabet = ['a', 'b', 'c', 'd', 'e', 'f', 'g', 'h', 'i', 'j', 'k', \
        'l', 'm', 'n', 'o', 'p', 'q', 'r', 's', 't', 'u', 'v', 'w', 'x', 'y', 'z']
    
    # this will help record the number of 
    # consonant seen already in a unique way
    count_consonant = set()
    
    # a dictionary that map every letter in the alphabet to 
    # a number.
    dict_alph_number = {letter.lower(): str(number+1) for number, letter in enumerate(alphabet)}
    
    # main code logic
    transformed_input = ''
    for location, caracter in enumerate(string_txt):
        if caracter.lower() in vowel:
            transformed_input += dict_alph_number[caracter.lower()]
        else:
            if caracter == " ":
                transformed_input += " "
            else:
                count_consonant.add(caracter.lower())
                transformed_input += caracter
    
    print(f"Original string:\n`{string_txt}`")      
    print(f"Transformed input : \n{transformed_input}")
    print(f"We have a notal of : {len(count_consonant)} consonants")