Created
December 14, 2013 21:00
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def queens(n): | |
queens_helper([], 1, n) | |
def queens_helper(occupied, col_to_test, n): | |
if len(occupied) == n: | |
print occupied | |
else: | |
# attempt to place queen | |
if is_free(col_to_test, occupied): | |
occupied.append(col_to_test) | |
queens_helper(occupied, 1, n) | |
# no space available | |
else: | |
next_col = col_to_test + 1 | |
# try next space in same row | |
if next_col <= n: | |
queens_helper(occupied, next_col, n) | |
# backtrack to previous row | |
else: | |
occupied, next_col = backtrack(occupied, n) | |
queens_helper(occupied, next_col, n) | |
def is_free(col_to_test, occupied): | |
if col_to_test in occupied: | |
return False | |
else: | |
return safe_diagonals(col_to_test, occupied) | |
def safe_diagonals(space, occupied): | |
for i in range(0, len(occupied)): | |
j = len(occupied) - i | |
if (occupied[i] == (space + j)) \ | |
or (occupied[i] == (space - j)): | |
return False | |
return True | |
def backtrack(occupied, n): | |
last_col_tried = n | |
while last_col_tried >= n: | |
occupied, last_col_tried = \ | |
back_one_step(occupied, last_col_tried) | |
next_col = last_col_tried + 1 | |
return occupied, next_col | |
def back_one_step(occupied, last_col_tried): | |
if occupied is not []: | |
last_col_tried = occupied[-1] | |
occupied.pop() | |
return occupied, last_col_tried | |
queens(4) |
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