Created
March 28, 2023 03:32
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| def remove_nth_node(head, n): | |
| i_slow = head | |
| j_fast = head | |
| # first we will move the fast pointer so that the distance between | |
| # j_fast - j_slow = n | |
| for _ in range(n): | |
| j_fast = j_fast.next | |
| if not j_fast: # return the next node to the slow pointer, if the | |
| # the number of nodes are less than n. | |
| return i_slow.next | |
| while j_fast.next: | |
| j_fast = j_fast.next | |
| i_slow = i_slow.next | |
| i_slow.next = i_slow.next.next | |
| return head |
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