KrishMunot

Keybase proof

I hereby claim:

• I am krishmunot on github.
• I am krishmunot (https://keybase.io/krishmunot) on keybase.
• I have a public key ASBYic12--HVv3lhN14eqxOzXRFkB9hxFNi248ZsjAR0KAo

To claim this, I am signing this object:

KrishMunot

Keybase proof

I hereby claim:

• I am krishmunot on github.
• I am krishmunot (https://keybase.io/krishmunot) on keybase.
• I have a public key ASBYic12--HVv3lhN14eqxOzXRFkB9hxFNi248ZsjAR0KAo

To claim this, I am signing this object:

KrishMunot

Keybase proof

I hereby claim:

• I am krishmunot on github.
• I am krishmunot (https://keybase.io/krishmunot) on keybase.
• I have a public key ASBYic12--HVv3lhN14eqxOzXRFkB9hxFNi248ZsjAR0KAo

To claim this, I am signing this object:

KrishMunot

Keybase proof

I hereby claim:

• I am krishmunot on github.
• I am krishmunot (https://keybase.io/krishmunot) on keybase.
• I have a public key ASBYic12--HVv3lhN14eqxOzXRFkB9hxFNi248ZsjAR0KAo

To claim this, I am signing this object:

KrishMunot

Keybase proof

I hereby claim:

• I am krishmunot on github.
• I am krishmunot (https://keybase.io/krishmunot) on keybase.
• I have a public key ASBYic12--HVv3lhN14eqxOzXRFkB9hxFNi248ZsjAR0KAo

To claim this, I am signing this object:

KrishMunot

/**
 * Copyright (c) 2016-present, Facebook, Inc.
 * All rights reserved.
 *
 * This source code is licensed under the BSD-style license found in the
 * LICENSE file in the root directory of this source tree. An additional grant
 * of patent rights can be found in the PATENTS file in the same directory.
 *
 * @flow
 */

KrishMunot

Keybase proof

I hereby claim:

• I am krishmunot on github.
• I am krishmunot (https://keybase.io/krishmunot) on keybase.
• I have a public key whose fingerprint is 82B4 D37B 4F17 8D85 DE58 CEA5 C734 9F4B 2E6D 77DC

To claim this, I am signing this object:

KrishMunot

from random import randint

print ('Welcome to Math. Press 00 to quit.')
score = 0
while True:
    a = randint(1, 100)
    b = randint(1, 100)
    yourAnswer = int(input('What is ' + str(a) + ' x ' + str(b) + '?\n--> '))
    if yourAnswer == '00':
        break