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2014-09-03 Problem of the Day solution in Swift
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// http://www.problemotd.com/problem/level-order-traversal/ | |
class BinaryTree<T> { | |
init(value: T) { | |
self.value = value | |
} | |
var value: T | |
var left: BinaryTree<T>? | |
var right: BinaryTree<T>? | |
} | |
let fTree = BinaryTree<String>(value:"F") | |
let bTree = BinaryTree<String>(value: "B") | |
let gTree = BinaryTree<String>(value: "G") | |
let aTree = BinaryTree<String>(value: "A") | |
let dTree = BinaryTree<String>(value: "D") | |
let iTree = BinaryTree<String>(value: "I") | |
let cTree = BinaryTree<String>(value: "C") | |
let eTree = BinaryTree<String>(value: "E") | |
let hTree = BinaryTree<String>(value: "H") | |
fTree.left = bTree | |
fTree.right = gTree | |
bTree.left = aTree | |
bTree.right = dTree | |
gTree.right = iTree | |
dTree.left = cTree | |
dTree.right = eTree | |
iTree.left = hTree | |
var nodesVisited: [BinaryTree<String>] = [] | |
var index = 0 | |
nodesVisited.append(fTree) | |
while index < nodesVisited.count { | |
let currentNode = nodesVisited[index] | |
println(currentNode.value) | |
if let left = currentNode.left { | |
nodesVisited.append(left) | |
} | |
if let right = currentNode.right { | |
nodesVisited.append(right) | |
} | |
index++ | |
} |
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