Created
August 5, 2016 10:28
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Implementation of quick sort in Ruby
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require 'rspec' | |
def q_sort(list) | |
list = Array(list) | |
case list.length | |
when 0 | |
[] | |
when 1 | |
list | |
when 2 | |
if list.first < list.last | |
list | |
else | |
list.reverse | |
end | |
else | |
head = list.first | |
tail = list.last(list.length - 1) | |
q_sort(tail.select{|x| x <= head}) + Array(head) + q_sort(tail.select{|x| x > head}) | |
end | |
end | |
describe "q_sort" do | |
it 'should return empty array for nil' do | |
list = nil | |
expect(q_sort list).to eq [] | |
end | |
it 'should return empty array for empty array' do | |
list = [] | |
expect(q_sort list).to eq [] | |
end | |
it 'should return same array for 1 length array' do | |
list = [3] | |
expect(q_sort list).to eq [3] | |
end | |
it 'should sort 2 length array' do | |
list = [1,6] | |
expect(q_sort list).to eq [1,6] | |
end | |
it 'should sort 2 length array' do | |
list = [9,6] | |
expect(q_sort list).to eq [6, 9] | |
end | |
it 'should do sort' do | |
list = [1, 10, 4, 6, 7, 3, 2] | |
expect(q_sort list).to eq [1, 2, 3, 4, 6, 7, 10] | |
end | |
it 'should do sort even containing duplicate value' do | |
list = [1, 10, 3, 3, 4, 10, 6, 3, 7, 3, 2] | |
expect(q_sort list).to eq [1, 2, 3, 3, 3, 3, 4, 6, 7, 10, 10] | |
end | |
end |
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