Created
August 10, 2017 00:04
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Solves the max decimal expansion length from 1 to N in a general way using the discrete logarithm. O(n^4)
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using System; | |
namespace Test | |
{ | |
class RepeatingDecimalLength | |
{ | |
// Solves the discrete logarithm problem in O(n^3). See https://arxiv.org/ftp/arxiv/papers/0912/0912.2269.pdf | |
// Returns k that solves for x^k = y (mod p) | |
public static UInt64 DiscreteLogarithm(UInt64 x, UInt64 y, UInt64 p) | |
{ | |
UInt64 lv_lng_x = x; | |
UInt64 lv_lng_y = y; | |
UInt64 lv_lng_p = p; | |
UInt64 lv_lng_vx1 = lv_lng_x; | |
UInt64 lv_lng_vx2 = 0; | |
UInt64 lv_lng_vy1 = lv_lng_y; | |
UInt64 lv_lng_vy2 = lv_lng_vy1; | |
UInt64 lv_lng_v1 = 1; | |
UInt64 k = 0; | |
for (System.UInt64 i = 0; i < lv_lng_p; i++) | |
{ | |
lv_lng_vx2 = 0; | |
for (System.UInt64 j = 0; j < lv_lng_x; j++) | |
{ | |
lv_lng_vx2 += lv_lng_vx1; | |
} | |
lv_lng_vx1 = lv_lng_vx2; | |
lv_lng_v1 += 1; | |
while (lv_lng_vx1 > lv_lng_p) | |
{ | |
lv_lng_vx1 -= lv_lng_p; | |
} | |
if (lv_lng_vy2 == lv_lng_vx1) | |
{ | |
k = lv_lng_v1; | |
break; | |
} | |
} | |
return k; | |
} | |
public static void Main(string[] args) | |
{ | |
// Multiplicative Order (Wolfram Alpha) | |
// The multiplicative order of 10 mod an integer n relatively prime | |
// to 10 gives the period of the decimal expansion of the reciprocal | |
// of n (Glaisher 1878, Lehmer 1941). | |
UInt64 k = 0; | |
int num = 0; | |
for (int i = 0; i < 1000; i++) | |
{ | |
var result = DiscreteLogarithm(10, 1, (UInt64)i); | |
if (result > k) | |
{ | |
k = result; | |
num = i; | |
Console.WriteLine("{0} has {1} decimal expansion length", num, k); | |
} | |
} | |
Console.ReadLine(); | |
} | |
} | |
} |
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