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Last active January 4, 2016 08:43
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Android 单击两次返回键退出程序
<span style="font-size:14px;">package com.test.twiceexit;
import java.util.Timer;
import android.app.Activity;
import android.os.Bundle;
import android.os.Handler;
import android.os.Message;
import android.view.KeyEvent;
import android.view.Menu;
import android.widget.Toast;
public class MainActivity extends Activity {
private static Boolean isQuit = false;
private long mExitTime = 0;
Timer timer = new Timer();
@Override
protected void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
setContentView(R.layout.activity_main);
}
@Override
public boolean onCreateOptionsMenu(Menu menu) {
// Inflate the menu; this adds items to the action bar if it is present.
getMenuInflater().inflate(R.menu.main, menu);
return true;
}
/**************************************************
* First
* ************************************************/
@Override
public boolean onKeyDown(int keyCode, KeyEvent event) {
if (keyCode == KeyEvent.KEYCODE_BACK) {
if (isQuit == false) {
isQuit = true;
Toast.makeText(getBaseContext(), "再按一次返回键退出程序",
Toast.LENGTH_SHORT).show();
TimerTask task = null;
task = new TimerTask() {
public void run() {
isQuit = false;
}
};
timer.schedule(task, 2000);
} else {
finish();
System.exit(0);
}
}
return false;
}
/**************************************************
* Second
* ************************************************/
@Override
public boolean onKeyDown(int keyCode, KeyEvent event) {
if (keyCode == KeyEvent.KEYCODE_BACK) {
if ((System.currentTimeMillis() - mExitTime) > 2000) {//
// 如果两次按键时间间隔大于2000毫秒,则不退出
Toast.makeText(this, "再按一次退出程序", Toast.LENGTH_SHORT).show();
mExitTime = System.currentTimeMillis();// 更新mExitTime
} else {
System.exit(0);// 否则退出程序
}
return true;
}
return super.onKeyDown(keyCode, event);
}
/**************************************************
* Third
* ************************************************/
Handler mHandler = new Handler() {
@Override
public void handleMessage(Message msg) {
super.handleMessage(msg);
isQuit = false;
}
};
@Override
public boolean onKeyDown(int keyCode, KeyEvent event) {
if (keyCode == KeyEvent.KEYCODE_BACK) {
if (!isQuit) {
isQuit = true;
Toast.makeText(getApplicationContext(), "再按一次退出程序",
Toast.LENGTH_SHORT).show();
// 利用handler延迟发送更改状态信息
mHandler.sendEmptyMessageDelayed(0, 2000);
} else {
finish();
System.exit(0);
}
}
return false;
}
}
</span>
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