Liudx1985

from io import StringIO
import sys

old_stdout = sys.stdout
sys.stdout = mystdout = StringIO()

# blah blah lots of code ...
print("fuck me god")
sys.stdout = old_stdout

Liudx1985

MPI实践起来真是有点困难，因为好多外国网站上不去，只能自己摸索：
1.setup mpich2
mpiexec -remove to remove account for each computer node
mpiexec -register to add account for each computer 'node'
mpiexec -validate to validate the account
 
Notice ,you must create a account(username/password all same) for all nodes on windows.
 
2.build boost.mpi
修改boost_1_47_0\tools\build\v2\tools\mpi.jam文件，修改的地方如下：

Liudx1985

# -*-  encoding=UTF-8 -*-
#!/usr/bin/env python
from Hello import *; # import internal c++ module
a = World()
a.set("Liudx")
print("Hello", a.greet())
print(identity(red), identity(color(2)), identity(color.blue))

k = a.t
k.a = 10;

Liudx1985

{
     "cmd": ["g++", "-std=c++1y", "${file}", "-O2", "-Wall", "-o", "${file_path}/${file_base_name}"], // For GCC On Windows and Linux
     //"cmd": ["CL", "/Fo${file_base_name}", "/O2", "${file}"],     // For CL on Windows Only
     "file_regex": "^(..[^:]*):([0-9]+):?([0-9]+)?:? (.*)$",
     "working_dir": "${file_path}",
     "selector": "source.c, source.c++",

     "variants":
     [
          {

Liudx1985

 
Fibonacci f(n+1)=f(n)+f(n-1) n >= 1
 
1. sum(f(n)^2) = f(n)*f(n+1)
证明如下，面积之和相等

# 绘图代码如下
import matplotlib.pyplot as plt
from matplotlib.path import Path
import matplotlib.patches as patches

Liudx1985

# -*-  coding:UTF-8 -*-
#!/usr/bin/env python
'''
Clear the directory using filter 
'''

import os.path
import sys,os
import stat
import re

Liudx1985

#include <vector>
#include <iostream>
#include "d:/workspace/dxh/testUlt.h"
using namespace std;
 //计算二项式系数C(n,k)
int Binomial(int n, int k) {
    int result[n + 1][k + 1];
    for(int i = 0; i <= n; ++i)        //按行来填矩阵
    {

Liudx1985

#include <iostream>
#include <cstdio>
#include <map>
#include <algorithm>

using namespace std;

// 双射函数
// proven : 
// as 

Liudx1985

#lang racket
;  applicative-order Y-combinator.
; Y: The function that takes a function f and returns f (f (f (f (···))))
(define Y
  (lambda (le)
    ((lambda (f) (f f))
     (lambda (f)
       (le (lambda (x) ((f f) x)))))))

Liudx1985

#lang racket
;;; 以下三个定义 env0, ent-env, lookup 是对环境(environment)的基本操作:

;; 空环境
(define env0 '())

;; 扩展。对环境 env 进行扩展，把 x 映射到 v，得到一个新的环境
(define ext-env
  (lambda (x v env)
    (cons `(,x . ,v) env)))