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Converting a mapped drive letter to a network path using C#
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// Source: https://www.wiredprairie.us/blog/index.php/archives/22 | |
using System; | |
using System.Collections.Generic; | |
using System.Linq; | |
using System.Text; | |
using System.Runtime.InteropServices; | |
using System.IO; | |
namespace WiredPrairie.Samples | |
{ | |
public static class Pathing | |
{ | |
[DllImport("mpr.dll", CharSet = CharSet.Unicode, SetLastError = true)] | |
public static extern int WNetGetConnection( | |
[MarshalAs(UnmanagedType.LPTStr)] string localName, | |
[MarshalAs(UnmanagedType.LPTStr)] StringBuilder remoteName, | |
ref int length); | |
/// <summary> | |
/// Given a path, returns the UNC path or the original. (No exceptions | |
/// are raised by this function directly). For example, "P:\2008-02-29" | |
/// might return: "\\networkserver\Shares\Photos\2008-02-09" | |
/// </summary> | |
/// <param name="originalPath">The path to convert to a UNC Path</param> | |
/// <returns>A UNC path. If a network drive letter is specified, the | |
/// drive letter is converted to a UNC or network path. If the | |
/// originalPath cannot be converted, it is returned unchanged.</returns> | |
public static string GetUNCPath(string originalPath) | |
{ | |
StringBuilder sb = new StringBuilder(512); | |
int size = sb.Capacity; | |
// look for the {LETTER}: combination ... | |
if (originalPath.Length > 2 && originalPath[1] == ':') | |
{ | |
// don't use char.IsLetter here - as that can be misleading | |
// the only valid drive letters are a-z && A-Z. | |
char c = originalPath[0]; | |
if ((c >= 'a' && c <= 'z') || (c >= 'A' && c <= 'Z')) | |
{ | |
int error = WNetGetConnection(originalPath.Substring(0, 2), | |
sb, ref size); | |
if (error == 0) | |
{ | |
DirectoryInfo dir = new DirectoryInfo(originalPath); | |
string path = Path.GetFullPath(originalPath) | |
.Substring(Path.GetPathRoot(originalPath).Length); | |
return Path.Combine(sb.ToString().TrimEnd(), path); | |
} | |
} | |
} | |
return originalPath; | |
} | |
} | |
} |
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error is always 1201 !!
any help !