Created
April 3, 2023 05:09
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This is a solution for the 'Drawing book' problem by hackerrank. It was made in Javascript (Node js)
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function pageCount(n, p) { | |
// Write your code here | |
//Identificar desde que lado empezaremos | |
let foundPage = false; | |
let currentPages = 0; | |
let counts = 0; | |
let tipoDeNumero = 0; | |
if(n%2!=0){ | |
//Numero par = 0 | |
//Numero impar = 1 | |
tipoDeNumero = 1; | |
} | |
if(p<=n/2){ | |
//left side | |
currentPages = [0,1]; | |
counts = 0; | |
while(!foundPage){ | |
//Buscamos en el arreglo si coincide p | |
if(currentPages.includes(p)){ | |
foundPage = true; | |
break; | |
} | |
//sumamos un count | |
counts++; | |
//Actualizamos las paginas | |
currentPages[0] = currentPages[0] + 2; | |
currentPages[1] = currentPages[1]+2; | |
} | |
} | |
else{ | |
//right side | |
//Si el numero es par entonces el arreglo empieza en [n, n+1] | |
if(tipoDeNumero==0) | |
{ | |
currentPages = [n,n+1] | |
} | |
else | |
{ | |
currentPages = [n-1,n]; | |
} | |
counts = 0; | |
while(!foundPage){ | |
//Buscamos en el arreglo si coincide p | |
if(currentPages.includes(p)){ | |
foundPage = true; | |
break; | |
} | |
//sumamos un count | |
counts++; | |
//Actualizamos las paginas | |
currentPages[0] = currentPages[0] - 2; | |
currentPages[1] = currentPages[1] - 2; | |
} | |
} | |
return counts; | |
} |
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