This is a solution for the 'Electronics shop' Challenge by Hackerrank

Electronics Shop Hackerrank -Solution

function getMoneySpent(keyboards, drives, b) {
    /*
     * Write your code here.
     */
    //Given an keyboards array an a drives array
    //We've gotta find how many possibles
    //'Combinations' are given a budget
    //Example: 
    //keyboards = [40,25,30,60]
    //drives = [10,12,14,7,18]
    //budget = 74
    //Possibles ways:
    // 40+10
    // 40 +12
   
    let mostExpensive = 0;
    keyboards.forEach(keyboard =>{
        //Compare every drives
        drives.forEach(drive=>{
          if((drive+keyboard<=b)&& (drive+keyboard > mostExpensive)){
              mostExpensive = drive+keyboard
          }
        })
    })
    if(mostExpensive == 0){
        return -1
    }
    else{
        return mostExpensive;
    }

}