Calculating a factorials trailing zeroes

Factorials Trailing zeros Count

/*  When the given problem is to find number number of trailing zeros of the factorial, one is not required to 
find out the factorial.
Statement : factorial(5) = 120 	= 1*2*3*4*5
factorial(4) = 24	= 1*2*3*4
if it is observed the occurance of 5 or multiples of five is in direct proportion to number of trailing zeros
If however, expression contains powers of 5, then the trailing zeros increasing with power of 5.
factorial(25) = 1*...5*..10..*15*..20*..25
As expected number of trailing zero in above is expected to be 5, but since 25 is 5 power 2, it adds another zero 
hence final count is 6.
*/

int count = 0;

if (fact <= 4){
	return 0;}
	
else if (fact == 5){
	return 1;}
	
else {
	for (int i = 5; fact/i >= 1; i*=5) {
		count = count + (fact/i);}

return count;