functional solution of FizzBuzz task.

fizzbuzz.py

def FizzBuzz(number):
    is_mult_of_3 = lambda n: (n % 3) == 0
    is_mult_of_5 = lambda n: (n % 5) == 0
    if is_mult_of_3(number) and is_mult_of_5(number):
        return "FizzBuzz"
    elif is_mult_of_3(number):
        return "Fizz"
    elif is_mult_of_5(number):
        return "Buzz"
    else:
        return number

numbers = list(map(FizzBuzz,range(1,101)))
print(numbers)