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@MLKrisJohnson
Created July 20, 2023 13:50
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Swift hexdump function
import Cocoa
func printHexdump(data: Data) {
print("\n 0 1 2 3 4 5 6 7 8 9 a b c d e f")
print("-----------------------------------------------------------------------------")
var i = 0
var bytes: [UInt8] = []
while i < data.count {
if i % 16 == 0 {
// Write ASCII at end of previous line
if !bytes.isEmpty {
print(" \(String(bytes: bytes, encoding: .ascii)!)")
bytes = []
}
// Write offset for this line
print(String(format: "%08x ", i), terminator: "")
}
else if i % 8 == 0 {
// Extra space between first eight bytes and last eight bytes
print(" ", terminator: "")
}
let byte = data[i]
print(String(format: " %02x", byte), terminator: "")
if byte >= 0x20 && byte <= 0x7e {
bytes.append(byte)
} else {
bytes.append(0x2e) // '.'
}
i += 1
}
// Handle any remaining whitespace to fill 16-byte line.
while i % 16 != 0 {
if i % 8 == 0 {
// Extra space between first eight bytes and last eight bytes
print(" ", terminator: "")
}
print(" ..", terminator: "")
bytes.append(0x20) // ' '
i += 1
}
if !bytes.isEmpty {
print(" \(String(bytes: bytes, encoding: .ascii)!)")
}
print("\n")
}
let data = "One ring to rule them all, one ring to find them, one ring to bring them close and in the darkness bind them!".data(using: .utf8)!
printHexdump(data: data)
/* Example output
0 1 2 3 4 5 6 7 8 9 a b c d e f
-----------------------------------------------------------------------------
00000000 4f 6e 65 20 72 69 6e 67 20 74 6f 20 72 75 6c 65 One ring to rule
00000010 20 74 68 65 6d 20 61 6c 6c 2c 20 6f 6e 65 20 72 them all, one r
00000020 69 6e 67 20 74 6f 20 66 69 6e 64 20 74 68 65 6d ing to find them
00000030 2c 20 6f 6e 65 20 72 69 6e 67 20 74 6f 20 62 72 , one ring to br
00000040 69 6e 67 20 74 68 65 6d 20 63 6c 6f 73 65 20 61 ing them close a
00000050 6e 64 20 69 6e 20 74 68 65 20 64 61 72 6b 6e 65 nd in the darkne
00000060 73 73 20 62 69 6e 64 20 74 68 65 6d 21 .. .. .. ss bind them!
*/
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