Check if password includes user name or part of it

check_username_in_password.js

function checkPasswordForUserName(userFullName, userPass) {
  const userNamesList = userFullName.toLowerCase().split(" ");
  const firstThreeChars = userFullName.substring(0, 3);
  const lowerCasePassword = userPass.toLowerCase();
  const isUserNameInPassword = (name) => (
    lowerCasePassword.includes(name) ||
    lowerCasePassword.includes(firstThreeChars)
  );
  
  return userNamesList.some(isUserNameInPassword);
}

//usage;; this will return true that means the password includes name of user!
checkPasswordForUserName("Mahbub Rahman", "mahbub343345");

Hey @MahbbRah, great gist, thanks for sharing!

How about we ignore the letter case for a more precise validation?
Also, I've made some changes on the code following functional programming standards, what do you think?

function checkPasswordForUserName(userFullName, userPass) {
  const userNamesList = userFullName.toLowerCase().split(" ");
  const firstThreeChars = userFullName.substring(0, 3);
  const lowerCasePassword = userPass.toLowerCase();
  const isUserNameInPassword = (name) => (
    lowerCasePassword.includes(name) ||
    lowerCasePassword.includes(firstThreeChars)
  );
  
  return userNamesList.some(isUserNameInPassword);
}

Hey @MahbbRah, great gist, thanks for sharing!

How about we ignore the letter case for a more precise validation?
Also, I've made some changes on the code following functional programming standards, what do you think?

function checkPasswordForUserName(userFullName, userPass) {
  const userNamesList = userFullName.toLowerCase().split(" ");
  const firstThreeChars = userFullName.substring(0, 3);
  const lowerCasePassword = userPass.toLowerCase();
  const isUserNameInPassword = (name) => (
    lowerCasePassword.includes(name) ||
    lowerCasePassword.includes(firstThreeChars)
  );
  
  return userNamesList.some(isUserNameInPassword);
}

This one super cool!, Thanks for the improvement!