CracklePop

cracklepop.py

#!/usr/bin/env python
"""Save as: cracklepop.py

I also looked into doing it entirely with regex and ran across this very
interesting post (I confess I only partially understand it, but it's an 
interesting discussion): https://stackoverflow.com/a/13223927
"""

# The normal one:
for num in range(1, 101):
    if not num % 15:
        print('CracklePop')
    elif not num % 3:
        print('Crackle')
    elif not num % 5:
        print('Pop')
    else:
        print(num)

# The cheeky (bash-curl-sed) one:
# curl -s 'https://raw.githubusercontent.com/Keith-S-Thompson/fizzbuzz-polyglot/master/expected-output.txt' | sed 's/Fizz/Crackle/g;s/Buzz/Pop/g'

# Testing the normal one with a version of the cheeky-one (assuming you have
# pytest installed, run the test with `pytest cracklepop.py`):
import re
import requests


def cracklepops(start=1, end=100):
    result = []
    for num in range(1, end + 1):
        if not num % 15:
            result.append('CracklePop')
        elif not num % 3:
            result.append('Crackle')
        elif not num % 5:
            result.append('Pop')
        else:
            result.append(str(num))
    return result


def test_cracklepops():
    url = 'https://raw.githubusercontent.com/Keith-S-Thompson/fizzbuzz-polyglot/master/expected-output.txt'
    response = requests.get(url)
    lines = [line.decode("utf-8") for line in response.iter_lines()]
    expected_cracklepops = [
        line.replace('Fizz', 'Crackle').replace('Buzz', 'Pop')
        for line in lines
    ]
    actual_cracklepops = cracklepops()

    assert actual_cracklepops == expected_cracklepops