Created
August 27, 2013 13:25
-
-
Save MartinThoma/6353473 to your computer and use it in GitHub Desktop.
Automatically find all homomorphisms between (Z/nZ, *) and (Z/mZ, *).
This can easily be adjusted to find homomorphisms between (Z/nZ, +) and (Z/mZ, +)
This file contains bidirectional Unicode text that may be interpreted or compiled differently than what appears below. To review, open the file in an editor that reveals hidden Unicode characters.
Learn more about bidirectional Unicode characters
#!/usr/bin/env python | |
# -*- coding: utf-8 -*- | |
def isGroupHomomorphism(phi, group1, group2, verbose=False): | |
for a, b in product(group1['set'], group2['set']): | |
inner = group1['operator'](a, b) | |
outer = group2['operator'](phi(a), phi(b)) | |
if verbose: | |
print("f(%i) = %i, f(%i) = %i f(%i)=%i=%i" % (a, phi(a), b, phi(b), inner, phi(inner), outer)) | |
if phi(inner) != outer: | |
return False | |
return True | |
def getZModPlusGroup(n): | |
group = {} | |
group['name'] = "Z/" + str(n) + "Z" | |
group['set'] = list(range(1,n)) | |
group['operator'] = lambda x, y: (x*y)%n | |
return group | |
if __name__ == "__main__": | |
group1 = getZModPlusGroup(5) | |
group2 = getZModPlusGroup(5) | |
from itertools import product | |
checkedCounter = 0 | |
homCounter = 0 | |
candidates = len(group2['set'])**len(group1['set']) | |
if candidates > 10000000: | |
print("Warning! This will test %i candidates!" % candidates) | |
for t in product(group2['set'], repeat=len(group1['set'])): #mapping from group1 to elements from group2 | |
checkedCounter += 1 | |
phi = lambda x: t[x-1] #* / + | |
if 1==2 and phi(0) != 0: | |
continue | |
else: | |
if isGroupHomomorphism(phi, group1, group2): | |
#isGroupHomomorphism(phi, group1, group2, True) | |
homCounter += 1 | |
print(group1['name'] + ":\t" + str(group1['set'])) | |
print(group2['name'] + ":\t" + str(t)) | |
print "#"*25 | |
print("Checked %i candidates. %i of them were homomorphisms." % (checkedCounter, homCounter)) |
Sign up for free
to join this conversation on GitHub.
Already have an account?
Sign in to comment