Created
February 4, 2014 13:16
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Lyndon word or lexicographically minimal string rotation
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#include <cstdio> | |
#include <cstring> | |
using namespace std; | |
const int N = 1213; | |
char a[N+1]; | |
// n > 0 | |
int lyndon_word(const char *a, int n) | |
{ | |
int i = 0, j = 1, k; | |
while (j < n) { | |
// Invariant: i < j and indices in [0,j) \ i cannot be the first optimum | |
for (k = 0; k < n && a[(i+k)%n] == a[(j+k)%n]; k++); | |
if (a[(i+k)%n] <= a[(j+k)%n]) { | |
// if k < n | |
// foreach p in [j,j+k], s_p > s_{p-(j-i)} | |
// => [j,j+k] are all suboptimal | |
// => indices in [0,j+k+1) \ i are suboptimal | |
// else | |
// None of [j,j+k] is the first optimum | |
j += k+1; | |
} else { | |
// foreach p in [i,i+k], s_p > s_{p+(j-i)} | |
// => [i,i+k] are all suboptimal | |
// => [0,j) and [0,i+k+1) are suboptimal | |
// if i+k+1 < j | |
// j < j+1 and indices in [0,j+1) \ j are suboptimal | |
// else | |
// i+k+1 < i+k+2 and indices in [0,i+k+2) \ (i+k+1) are suboptimal | |
i += k+1; | |
if (i < j) | |
i = j++; | |
else | |
j = i+1; | |
} | |
} | |
// j >= n => [0,n) \ i cannot be the first optimum | |
return i; | |
} | |
int main() | |
{ | |
while (gets(a)) { | |
printf("%d\n", lyndon_word(a, (int)strlen(a))); | |
} | |
} |
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