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Tweedie distribution in Stan
data {
int N;
int M;
real<lower=0> Y[N];
}
parameters {
real<lower=0> mu;
real<lower=0> phi;
real<lower=1, upper=2> theta;
}
transformed parameters {
real lambda = 1/phi*mu^(2-theta)/(2-theta);
real alpha = (2-theta)/(theta-1);
real beta = 1/phi*mu^(1-theta)/(theta-1);
}
model {
mu ~ cauchy(0, 5);
phi ~ cauchy(0, 5);
for (n in 1:N) {
if (Y[n] == 0) {
target += -lambda;
} else {
vector[M] ps;
for (m in 1:M)
ps[m] = poisson_lpmf(m | lambda) + gamma_lpdf(Y[n] | m*alpha, beta);
target += log_sum_exp(ps);
}
}
}
library(rstan)
library(tweedie)
stanmodel <- stan_model(file='model/model.stan')
N1 <- 200
M1 <- 30
Y1 <- rtweedie(N1, power=1.3, mu=1, phi=1)
data1 <- list(N=N1, M=M1, Y=Y1)
fit1 <- sampling(stanmodel, data=data1)
N2 <- 1000
M2 <- 30
Y2 <- rtweedie(N2, power=1.01, mu=3, phi=1)
data2 <- list(N=N2, M=M2, Y=Y2)
fit2 <- sampling(stanmodel, data=data2)
@nazi123
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nazi123 commented Nov 18, 2019

Mr. Matsuura, I'm so sorry for my mistake. your comments and your blog content were really helpful for me.
May you introduce me, a book or an article with a more complete description about this sentence: "Under the assumption that theta <1.3 , lambda will be less than 15"

Thanks a million

@MatsuuraKentaro
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Author

MatsuuraKentaro commented Nov 18, 2019

First, check the data distribution. Next, look at which of the following figures is similar.
https://cdn-ak.f.st-hatena.com/images/fotolife/S/StatModeling/20201106/20201106201645.png
Then you can see the approximate range of parameters.

@nazi123
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nazi123 commented Nov 18, 2019

I got it, many thanks.

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