download_file.py

''' 
    This code snippet was found on Stack Overflow
    Question: http://stackoverflow.com/questions/34079/how-to-specify-an-authenticated-proxy-for-a-python-http-connection
    Answer: http://stackoverflow.com/a/34116/1367612
'''

import urllib2


TRANSFER_PROTOCOL = "https"
PROXY_SERVER_ADDRESS = ""
USER_NAME = ""
PASSWORD = ""
PROXY_PORT = "8000"


def downloadFile(url):
    '''
        stupid doc string
    '''
    file_name = url.split('/')[-1]

    proxy = urllib2.ProxyHandler(TRANSFER_PROTOCOL, 
        '{0}://{1}:{2}@{3}:{4}'.format(TRANSFER_PROTOCOL, 
            USER_NAME, PASSWORD, PROXY_SERVER_ADDRESS, PROXY_PORT))
    auth = urllib2.HTTPBasicAuthHandler()
    opener = urllib2.build_opener(proxy, auth, urllib2.HTTPHandler)
    urllib2.install_opener(opener)

    opend_url = urllib2.urlopen(url)
    file_handle = open(file_name, 'wb')
    meta = opend_url.info()
    file_size = int(meta.getheaders("Content-Length")[0])
    print "Downloading: %s Bytes: %s" % (file_name, file_size)

    file_size_dl = 0
    block_sz = 8192
    while True:
        buffer = opend_url.read(block_sz)
        if not buffer:
            break

        file_size_dl += len(buffer)
        file_handle.write(buffer)
        status = r"%10d  [%3.2f%%]" % (file_size_dl, 
            file_size_dl * 100. / file_size)
        status = status + chr(8)*(len(status)+1)
        print status,

    file_handle.close()


URLS = [
  # files, comma seperated, that you want to download.
]

for url in URLS:
    downloadFile(url)