PKCS7 Padding in python

aes_tool.py

def _pad(text, block_size):
    """
    Performs padding on the given plaintext to ensure that it is a multiple
    of the given block_size value in the parameter. Uses the PKCS7 standard
    for performing padding.
    """
    no_of_blocks = math.ceil(len(text)/float(block_size))
    pad_value = int(no_of_blocks * block_size - len(text))

    if pad_value == 0:
        return text + chr(block_size) * block_size
    else:
        return text + chr(pad_value) * pad_value

why just not use:

    pad_value = block_size - len(text) % block_size

    return text + chr(pad_value) * pad_value

@cono I'm afraid 10 years ago is far too long for me to remember why I did this :)