Created
December 6, 2019 13:55
-
-
Save MinecraftFuns/aa2a98056e0f106d00535649174b594b to your computer and use it in GitHub Desktop.
CF1264C Beautiful Mirrors with queries
This file contains bidirectional Unicode text that may be interpreted or compiled differently than what appears below. To review, open the file in an editor that reveals hidden Unicode characters.
Learn more about bidirectional Unicode characters
#include <bits/stdc++.h> | |
template <class T> | |
inline void read(T &x) | |
{ | |
x = 0; | |
register char c = getchar(); | |
register bool f = 0; | |
while (!isdigit(c)) | |
f ^= c == '-', c = getchar(); | |
while (isdigit(c)) | |
x = x * 10 + c - '0', c = getchar(); | |
if (f) | |
x = -x; | |
} | |
template <class T> | |
inline void print(T x) | |
{ | |
if (x < 0) | |
putchar('-'), x = -x; | |
if (x > 9) | |
print(x / 10); | |
putchar(x % 10 + '0'); | |
} | |
template <class T> | |
inline void print(T x, char c) { print(x), putchar(c); } | |
const int N = 2e5 + 10, mod = 998244353; | |
struct z | |
{ | |
int x; | |
z(int x = 0) : x(x) {} | |
friend inline z operator*(z a, z b) { return (long long)a.x * b.x % mod; } | |
friend inline z operator-(z a, z b) { return (a.x -= b.x) < 0 ? a.x + mod : a.x; } | |
friend inline z operator+(z a, z b) { return (a.x += b.x) >= mod ? a.x - mod : a.x; } | |
} inv100, p[N]; | |
inline z fpow(z a, int b) | |
{ | |
z s(1); | |
for (; b; b >>= 1, a = a * a) | |
if (b & 1) | |
s = s * a; | |
return s; | |
} | |
struct pair | |
{ | |
z x, y; | |
inline z set(z k) { return x * k + y; } | |
friend inline pair operator*(const pair &x, const pair &y) { return (pair){x.x * y.x, x.x * y.y + x.y}; } | |
}; | |
struct seg | |
{ | |
struct node | |
{ | |
int l, r, mid; | |
pair x; | |
} p[N << 2]; | |
void build(int u, int l, int r, pair foo(int)) | |
{ | |
p[u].l = l, p[u].r = r, p[u].mid = (l + r) >> 1; | |
if (l == r) | |
{ | |
p[u].x = foo(l); | |
return; | |
} | |
build(u << 1, l, p[u].mid, foo); | |
build(u << 1 | 1, p[u].mid + 1, r, foo); | |
p[u].x = p[u << 1].x * p[u << 1 | 1].x; | |
} | |
void modify(int u, int k, pair x) | |
{ | |
if (p[u].l == p[u].r) | |
{ | |
p[u].x = x; | |
return; | |
} | |
modify(k <= p[u].mid ? u << 1 : u << 1 | 1, k, x); | |
p[u].x = p[u << 1].x * p[u << 1 | 1].x; | |
} | |
pair query(int u, int l, int r) | |
{ | |
if (p[u].l == l && p[u].r == r) | |
return p[u].x; | |
if (r <= p[u].mid) | |
return query(u << 1, l, r); | |
if (l > p[u].mid) | |
return query(u << 1 | 1, l, r); | |
return query(u << 1, l, p[u].mid) * query(u << 1 | 1, p[u].mid + 1, r); | |
} | |
} f, g, h, res; | |
int n, m; | |
std::set<int> set; | |
pair calc(int l, int r) | |
{ | |
z a = f.query(1, l, r).set(0); | |
z b = g.query(1, l, r).set(1); | |
z c = h.query(1, l, r).set(0); | |
z inv = fpow(1 - a, mod - 2); | |
// printf("calc %d %d >> %d %d %d >> %d %d\n",l,r,a.x,b.x,c.x,b*inv.x,c*inv.x); | |
return (pair){b * inv, c * inv}; | |
} | |
int main() | |
{ | |
#ifdef memset0 | |
freopen("1.in", "r", stdin); | |
#endif | |
read(n), read(m), p[0] = 1, inv100 = fpow(100, mod - 2); | |
for (int i = 1; i <= n; i++) | |
read((int &)p[i]), p[i] = p[i] * inv100; | |
set.insert(0), set.insert(1), set.insert(n + 1); | |
f.build(1, 0, n, [](int i) { return (pair){p[i], 1 - p[i]}; }); | |
g.build(1, 0, n, [](int i) { return (pair){p[i], z(0)}; }); | |
h.build(1, 0, n, [](int i) { return (pair){p[i], z(1)}; }); | |
res.build(1, 0, n, [](int k) { | |
if (k == 0) | |
return calc(0, 0); | |
if (k == 1) | |
return calc(1, n); | |
return (pair){1, 0}; | |
}); | |
for (int x, i = 1; i <= m; i++) | |
{ | |
read(x); | |
// printf(">> %d\n",x); | |
if (set.find(x) == set.end()) | |
{ | |
set.insert(x); | |
auto it = set.find(x); | |
int l = *std::prev(it), r = *std::next(it); | |
res.modify(1, l, calc(l, x - 1)); | |
res.modify(1, x, calc(x, r - 1)); | |
} | |
else | |
{ | |
auto it = set.find(x); | |
int l = *std::prev(it), r = *std::next(it); | |
res.modify(1, l, calc(l, r - 1)); | |
res.modify(1, x, {1, 0}); | |
set.erase(it); | |
} | |
printf("%d\n", (res.query(1, 0, n).set(0) - 1).x); | |
// for(int i=0;i<=n;i++)printf("[%d %d]%c",res.query(1,i,i).x.x,res.query(1,i,i).y.x," \n"[i==n]); | |
} | |
// printf(">> %d\n",(z(3)*fpow(4,mod-2)).x); | |
} |
Sign up for free
to join this conversation on GitHub.
Already have an account?
Sign in to comment