Created
May 5, 2019 11:22
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New Companies Hackerrank solution (two solutions)
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SELECT company.company_code,company.founder, | |
count(distinct Lead_manager.lead_manager_code), | |
count(distinct Senior_manager.senior_manager_code), | |
count(distinct Manager.manager_code),count(distinct Employee.employee_code) | |
from company | |
INNER JOIN Lead_Manager | |
on company.company_code = Lead_Manager.company_code | |
INNER JOIN Senior_Manager | |
on company.company_code = Senior_Manager.company_code | |
INNER JOIN Manager | |
on company.company_code = Manager.company_code | |
INNER JOIN Employee | |
on company.company_code = Employee.company_code | |
GROUP BY company.company_code,company.founder | |
order by company.company_code asc | |
-- -------------------------------- ANOTHER SOLUTION ( BETTER ) | |
select E.company_code, C.founder, | |
count(distinct lead_manager_code), count(distinct senior_manager_code), | |
count(distinct manager_code), count(distinct employee_code) | |
from Employee E inner join Company C on E.company_code = C.company_code group by E.company_code, C.founder order by E.company_code |
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