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Nan-Zhang/BitWise

Last active August 29, 2015 14:06
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BitWise
show ith of a: a & 1 << i
reset ith of a: a &= ~(1 << i)
populate the result: result |= 1 << i
(-i) & i; //NOTE from right to left, get first '1' and other bits is '0'
n & (n - 1) == 0 check if n is power of 2
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