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func isEven(number: Int) -> Bool { | |
return number % 2 == 0 | |
} | |
//isEven(31) | |
func isDivisible(x: Int, by y: Int) -> Bool { | |
return x % y == 0 | |
} | |
//isDivisible(30, by: 5) | |
/// DON'T EVER DO THIS BECAUSE THIS IS INEFFICIENT AF | |
func numberOfDigitsByConvertingToString(x: Int) -> Int { | |
return String(x).characters.count | |
} | |
//numberOfDigitsByConvertingToString(1100000) | |
func numberOfDigits(x: Int) -> Int { | |
var temporaryValue = x; | |
var count = 0 | |
while temporaryValue != 0 { | |
temporaryValue /= 10 | |
count++ | |
} | |
return count | |
} | |
//numberOfDigits(1100000) | |
func fizzBuzz(fizzAt fizz: Int, buzzAt buzz: Int, max: Int) { | |
for count in 1...max { | |
if count % (fizz * buzz) == 0 { | |
print("FizzBuzz") | |
} else if count % fizz == 0 { | |
print("Fizz") | |
} else if count % buzz == 0 { | |
print("Buzz") | |
} else { | |
print("\(count)") | |
} | |
} | |
} | |
//fizzBuzz(fizzAt: 3, buzzAt: 5, max: 69) | |
/// This is an interesting method to do it but it's harder to understand. | |
/// You don't have to worry about it yet, probably no one does something like this in real apps. | |
/// For 3 and 5 only. | |
func bitwiseFizzBuzz(max max: Int) { | |
var mutatingMask = 0b110000010010010000011000010000 | |
let messages: [String?] = [ nil, "Fizz", "Buzz", "FizzBuzz" ] | |
for count in 1...max { | |
let index = mutatingMask & 3 | |
if let message = messages[index] { | |
print(message) | |
} else { | |
print(count) | |
} | |
mutatingMask = mutatingMask >> 2 | index << 28 | |
} | |
} | |
//bitwiseFizzBuzz(max: 69) |
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