solve.py

import string

def xor(msg, key):
    o = ''
    for i in range(len(msg)):
        o += chr(ord(msg[i]) ^ ord(key[i % len(key)]))
    return o
  
msg="\x05F\x17\x12\x14\x18\x01\x0c\x0b4"
msg2=">\x1f\x00\x14\n\x08\x07Q\n\x0e"

# Phase 1 - Find part of key
part_of_msg = 'd4rk{'
p2 = '}c0de'

for i in range(len(msg)):
    candidate = xor(msg[i:i+len(part_of_msg)], part_of_msg)
    if candidate.isalnum():
        print "front:", candidate

for i in range(len(msg2)):
    candidate2 = xor(msg2[i:i+len(p2)], p2)
    if candidate2.isalnum():
    	print "back:", candidate2

# key = "areyoudank"

# print "Flag:", xor(msg + msg2, key)