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| The origin of the question is http://stackoverflow.com/q/25949977/3185992 where user Sri asked about a problem he had. | |
| The problem is not that hard to solve, but the answers got me concerned that there must be a more elegant way of doing this. | |
| I wanted something with meaningful intermediate results, which is composable and not some nested for loops which at the end will result in the right thing. | |
| Problem description: | |
| ==================== | |
| Given two strings compute the count of characters which are not common in both of them. | |
| However each character "counts of its own", that is if a character is included in the first string 2 times and a single time in the second one, the right answer for this character is: 1. | |
| Example from the user: |