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k = 15 | |
m = 1<<k | |
tab = {} | |
pow2 = m<<2 -- any power of two larger works | |
for i=1,m do | |
tab[pow2+i] = 1 -- insert big elements | |
end |
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math.randomseed(2151) -- (2151) | |
n = 1<<23 | |
iterations = 100 | |
pow = 1<<31 | |
pow2 = pow>>1 | |
m = 15 | |
offset = 1<<m | |
it = offset |
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def binary(x) : | |
return format(x,'b') | |
def print_binary(x) : | |
print binary(x) | |
def iterate(superset,f) : | |
i = 0 | |
while True : | |
f(i) |
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#include <iostream> | |
#include <vector> | |
#include <cstdlib> | |
#include <ctime> | |
#include <cassert> | |
using namespace std; | |
int count; // to experiment a bit... | |
// divide and conquer shellsort with powers of two... |
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import itertools | |
M = {} | |
def look_and_say(atom,n) : | |
global M | |
a = atom | |
if n == 0 : | |
return 0 | |
b = "" |
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import itertools | |
def look_and_say(n) : | |
a = "0" | |
for i in xrange(n) : | |
b = "" | |
for c,l in itertools.groupby(a) : | |
b += bin(len(list(l)))[2:] + c | |
yield a | |
a = b |
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#include <iostream> | |
#include <cstdio> | |
#include <vector> | |
using namespace std; | |
#define oo (1<<28) | |
int solve(vector <string> m) | |
{ | |
int N = m.size(), M = m[0].length(); |
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gets.to_i.times do |i| | |
n, m, ps = gets.split.map(&:to_i) | |
players = (1..n).map do | |
name, sp, h = gets.split | |
sp, h = sp.to_i, h.to_i | |
[sp,h,name] | |
end | |
players.sort! | |
players.reverse! | |
team1, team2 = [], [] |
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#!/usr/bin/env ruby | |
# [Gedit Tool] | |
# Name=CodeForces | |
# Shortcut=<Control>F6 | |
# Languages=cpp | |
# Applicability=all | |
# Output=output-panel | |
# Input=nothing | |
# Save-files=document |
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require 'cairo' | |
#input and output come as arguments | |
input, output = ARGV | |
surface = Cairo::ImageSurface.from_png input | |
goal_data = surface.data | |
HEIGHT, WIDTH = surface.height, surface.width |
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