This python program will convert any given number to its binary form

any_number_to_binary.py

#accept a number, and return its binary form

x = float(raw_input('Enter a number: '))
isNeg = False

if x < 0:
    x = abs(x)
    isNeg = True
resultInt = ''
resultFlt = ''
result = ''
intPart = int(x)

fltPart = x - intPart

#print('Integer part: ' + str(intPart))
#print('Float part: ' + str(fltPart))

if x == 0:
    resultInt = '0'
    resultFlt = '0'
    result = resultInt + '.' + resultFlt
    print(result)

p = 0
#convert integer part to binary
while intPart > 0:
    resultInt = str(intPart%2) + resultInt
    intPart = intPart/2

#print('The binary representation of the int part is: ' + resultInt)

#convert float part to binary

#we want to find p such that 2^p*x is a whole number
while (((2**p) * fltPart)%1 !=0):
    p +=1

#print ('value of p is: ' + str(p))

#We cast (2^p)*x to an integer
num = int((2**p)*fltPart)
#print ('num is ' + str(num))
#we now convert this integer to binary

while num > 0:
    resultFlt = str(num%2) + resultFlt
    num = num/2
#figure out how many zeros are needed to the left of the result
for i in range(p - len(resultFlt)):
    resultFlt = '0' + resultFlt
#figure out where to place decimal
resultFlt = resultFlt[0:-p] + '.' + resultFlt[-p:]
#print ('The binary representation of the float part is: ' + resultFlt)
result = resultInt + resultFlt

if isNeg:
    result = '-' + result
    print('The binary representation of ' + str(x) + ' is : ' + result)
else:
    print('The binary representation of ' + str(x) + ' is : ' + result)