discord.py command to save modlogs to a yaml file. (Quick solution to a problem, better to use a database)

save_to_yaml.py

@commands.guild_only()
@commands.has_permissions(manage_guild=True)
@commands.command(name='modlog')
async def set_modlog(self, ctx, channel: discord.TextChannel):
    """Set the modlog channel"""
    with open('db/guild_settings.yaml', 'r+') as yaml_file:
        yaml_data = yaml.load(yaml_file)
        keys = list(yaml_data.keys())
        if f'{ctx.guild.id}' in keys:
            if yaml_data[f'{ctx.guild.id}']['modlog'] == str(channel.id):
                await ctx.send('Channel already set as modlog.')
                return yaml_file.close()
            else:
                with open('db/guild_settings.yaml', 'w') as f:
                    yaml_data[f'{ctx.guild.id}']['modlog'] = str(channel.id)
                    f.write(yaml.dump(yaml_data, default_flow_style=False))
                    await ctx.send(f'Updated modlog to `{channel}`')
                    yaml_file.close()
                    f.close()
        else:
            data = {
                f'{ctx.guild.id}': {
                    'modlog': f'{channel.id}'
                }
            }
            yaml.dump(data, yaml_file, default_flow_style=False)
            await ctx.send(f'Added `{channel}` as modlog')
            yaml_file.close()
            
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def get_modlog(ctx):
    try:
        with open('db/guild_settings.yaml', 'r') as yaml_file:
            data = yaml.load(yaml_file)
            return data[f'{ctx.guild.id}']['modlog']
    except KeyError:
        return None