solution_ten.py

def myfunc(x):
    out = []
    for i in range(len(x)):
        if i%2==0:
            out.append(x[i].lower())
        else:
            out.append(x[i].upper())
    return ''.join(out)

def myfunc(word):
letters = [*word]
result = ""
for index, item in enumerate(letters):
if index % 2 == 0:
result += item.upper()
else:
result += item.lower()
return result

def myfunc(st):
#print(st.split())
str1=''
counter=1
for index in st:

    if counter%2==0:
        str1+= index.upper()
    else:
        str1+=index.lower()
    counter+=1
return(str1)

print(myfunc('AnthropomorphismakhfB'))

def myfunc(*args):
word = ''
for letter in args:
if len(args) % 2 == 0:
word.append(letter.upper)
else:
word.append(letter.lower)

AttributeError Traceback (most recent call last)
Cell In[2], line 1
----> 1 myfunc('Avni')

Cell In[1], line 7, in myfunc(*args)
5 word.append(letter.upper)
6 else:
----> 7 word.append(letter.lower)

AttributeError: 'str' object has no attribute 'append'

A another approach that I have tried using args:

def myfunc(*args):
mystr = str(args)
new_list = list(mystr)
length = len(new_list)
order_list = []
final = ''
even = (mystr[0:length:2].lower())
l_even = len(even) - 1
odd = (mystr[1:length:2].upper())
l_odd = len(odd) - 1

while length !=0:
    if length%2 != 0:
        order_list.append(even[l_even])
        l_even = l_even - 1
    else:
        order_list.append(odd[l_odd])
        l_odd = l_odd - 1
    length = length -1
order_list.reverse()
for i in order_list:
    final = final + i
return final

this is good to add any number of arguments that can be fit for this usecase