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@Pierian-Data
Created March 1, 2018 17:19
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def myfunc(*args):
out = []
for num in args:
if num%2==0:
out.append(num)
return out
@Terry-Cherry
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def myfunc(*args):
return [x for x in args if x % 2 == 0]

@jayant9511
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def myfunc(*args):
out = []
for num in args:
if num%2==0:
out.append(num)
return out

@Tari5-code
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def myfunc(*args):
mylist = []
for num in args:
if num %2==0:
mylist.append(num)
return mylist

@harshchudasama
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def myfunc(*args):
mylist = []
for item in args:
if item %2 == 0:
mylist.append(item)
else:
pass
return mylist

@eoparada
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def myfunc(*args):
evenlist = []
for n in args:
if n%2==0:
evenlist.append(n)
else:
pass
return evenlist

myfunc(2,4,9,11,1)

@Jagdish-S-Patil
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def myfunc(*args):
evenlist=[]
for num in args:
if num%2==0:
evenlist.append(num)
else:
return evenlist

@alina13444
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ef myfunc(*args):
list = []
for num in args:
if numb%2 == 0:
list.append(num)
return list

@volkalik
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def myfunc(*args):
even_numbers = []
for x in args:
if x % 2 == 0:
even_numbers.append(x)
else:
pass
return even_numbers
myfunc(1,2,3,4,5)

@tulasiranganathan
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def myfunc(*args):
list = []
for num in args:
ifnum%2 == 0:
list.append(num)
return list

@Sreyaakrishna
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def myfunc(*args):
mylist = []
for num in args:
if num%2==0:
mylist.append(num)
return mylist

@anantharajp
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def myfunc(*a):
b = []
for i in a:
if i%2 == 0:
b.append(i)
return b

@tulasiranganathan
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def myfunc(*args):
list = []
for num in args:
if num % 2 = 0:
list.append(num)
return list

@natchaliw
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def myfunc(*args):
out =[]
for num in args :
if num % 2 == 0:
out.append(num)
return out

@LAMRA7
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LAMRA7 commented Dec 13, 2023

here I follow this Answer
Screenshot (780)

@harshinimamidipalli
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def myfunc(*args):
a=[]
for num in args:
if args%2==0:
a.append(args)
return a

@mykhailotm
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1st method
def myfunc(*args):
arg = []

for num in args:
    if num % 2 == 0:
        arg.append(num)
return arg

2nd method

def myfunc(*args):
return [num for num in args if num % 2 == 0]

@kabbo90909090
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def my_functiion (args):
out=[]
for num in args:
if num%2 ==0:
out.append(num)
return out

@Salonikr
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def myfunc(*args):
mylist=[]
for w in args:
if w%2==0:
mylist.append(w)
else:
pass
return mylist

@SubashriR-DS
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SubashriR-DS commented Feb 13, 2024

def myfunc(*args):
even_list=[ ]
for num in args:
if num % 2 ==0:
even_list.append(num)
else:
pass
return even_list

output
myfunc(2,4,5,6,7,8,9)
[2,4,6,8]

@NishaKarki1228
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def myfunc(*args):
x=[]
for items in args:
if items%2==0:
x.append(items)
return(x)

@VictoriaPoint
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a bit difficult one

def myfunc(*args):
out =[]
for item in args:
if item%2 == 0:
out.append(item)
return out

@saurabhlively-barclays
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mylist = []
def myfunc(*args):

for num in args:
    if num%2 == 0:
        mylist.append(num)
return mylist

res=myfunc(10,30,35)
print(res)

@Aixa-Cal
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def myfunc(*args):
out = []:
for num in args:
if num%2 == 0:
out.append(num)
return out

@sudheerkilani
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image

@Phan-Hoangg
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def myfunc(*args):
out = []
for num in args:
if num % 2 == 0:
out.append(num)
return out
print(myfunc(1,2,3,4))

@Jarbo1225
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def myfunc(*args):
out = []
for num in args:
if num%3==0:
out.append(n)
else:
return out
result = myfunc(3,6,9,12,15)
print (result)

@RogelioDaniel
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def myfunc(*args):
lista=[]
for num in args:
if num % 2 == 0:
lista.append(num)
return lista

@Avishruti
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def myfunc(*args):
x = []
for num in args:
if num%2==0:
x.append(num)
return x

@THANGAM2000
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def myfunc(*args):
return[args for args in args if args%2 == 0]
myfunc(13,54,6,78,9)
output:
[54,6,78]

@kevin17-86
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`def even_number_list(*numlist):
even_numbers = []

for num in numlist:
    if num % 2 == 0:
        even_numbers.append(num)
    else:
        pass

return even_numbers

print(even_number_list(1, 2, 3, 4, 5, 6))`

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